b^2-28b+27=

Solution for b^2-28b+27= equation:

Simplifying
b2 + -28b + 27 = 0

Reorder the terms:
27 + -28b + b2 = 0

Solving
27 + -28b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(1 + -1b)(27 + -1b) = 0

Subproblem 1
Set the factor '(1 + -1b)' equal to zero and attempt to solve:

Simplifying
1 + -1b = 0

Solving
1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1b = 0 + -1
-1b = 0 + -1

Combine like terms: 0 + -1 = -1
-1b = -1

Divide each side by '-1'.
b = 1

Simplifying
b = 1
Subproblem 2
Set the factor '(27 + -1b)' equal to zero and attempt to solve:

Simplifying
27 + -1b = 0

Solving
27 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-27' to each side of the equation.
27 + -27 + -1b = 0 + -27

Combine like terms: 27 + -27 = 0
0 + -1b = 0 + -27
-1b = 0 + -27

Combine like terms: 0 + -27 = -27
-1b = -27

Divide each side by '-1'.
b = 27

Simplifying
b = 27
Solution
b = {1, 27}